To get the let-through energy value of a particular breaker, you need to follow these steps:
- Determine the maximum short-circuit current at the breaker.
- Determine the protection tripping time of the breaker.
- Calculate the let-through energy using the formula I²t = (k² x S²) / t, where k is the thermal constant, S is the cross-sectional area of the conductor, and t is the protection tripping time.
- The maximum short-circuit current at the breaker is 50 kA.
- The protection tripping time of the breaker is 0.1 seconds.
- The thermal constant k for copper is 115, and the cross-sectional area S of a 63A breaker is 16 mm². Therefore, the let-through energy value of the breaker is:
1 Comments
Hello, Great post, was that I was looking for. Do you have a table for cross-sectional area S for Molded case CB. and the second thing is when I do this operation, I can not get the same result.
ReplyDeleteI²t = (115² x 16²) / 0.1 = 2,174,400 A²s
seems simple, but for me is 3,3856,000 A²s