Determining the energy let through of cable and protective device

Determining the energy let through of cable and protective device

 To get the let-through energy value of a particular breaker, you need to follow these steps:

  1. Determine the maximum short-circuit current at the breaker.
  2. Determine the protection tripping time of the breaker.
  3. Calculate the let-through energy using the formula I²t = (k² x S²) / t, where k is the thermal constant, S is the cross-sectional area of the conductor, and t is the protection tripping time.
Here is an example of how to calculate the let-through energy value of an ABB SACE rated 63A breaker:
  1. The maximum short-circuit current at the breaker is 50 kA.
  2. The protection tripping time of the breaker is 0.1 seconds.
  3. The thermal constant k for copper is 115, and the cross-sectional area S of a 63A breaker is 16 mm². Therefore, the let-through energy value of the breaker is:
I²t = (115² x 16²) / 0.1 = 2,174,400 A²sSo, the let-through energy value of an ABB SACE rated 63A breaker is 2,174,400 A²s.

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1 Comments

  1. Hello, Great post, was that I was looking for. Do you have a table for cross-sectional area S for Molded case CB. and the second thing is when I do this operation, I can not get the same result.
    I²t = (115² x 16²) / 0.1 = 2,174,400 A²s
    seems simple, but for me is 3,3856,000 A²s

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